Question

the numbers in the electron configurations shown below.
na: $1s^2 2s^c 2p^d 3s^e$
$c = \square$
$d = \square$
$e = \square$
done

Explanation:

Step1: Recall s - orbital capacity

The s - orbital can hold a maximum of 2 electrons. For the \(2s\) sub - shell, the exponent \(C\) represents the number of electrons in the \(2s\) sub - shell. Since s - orbitals hold 2 electrons, \(C = 2\).

Step2: Recall p - orbital capacity

The p - orbital can hold a maximum of 6 electrons. For the \(2p\) sub - shell, the exponent \(D\) represents the number of electrons in the \(2p\) sub - shell. So \(D=6\).

Step3: Determine electrons in \(3s\) for Na

Sodium (Na) has an atomic number of 11, which means it has 11 electrons. We already know that in the \(1s\) sub - shell there are 2 electrons, in the \(2s\) sub - shell there are 2 electrons, and in the \(2p\) sub - shell there are 6 electrons. Let the number of electrons in the \(3s\) sub - shell be \(E\). Then, using the formula for the total number of electrons: \(2 + C+D + E=11\). Substituting \(C = 2\) and \(D = 6\), we get \(2+2 + 6+E=11\), which simplifies to \(10 + E=11\), so \(E = 1\).

Answer:

\(C = 2\), \(D = 6\), \(E = 1\)