Question

this is an orbital diagram for the element... (use the element symbol or the correct spelling of the element name)

Explanation:

Step1: Count electrons in each orbital

1s has 2 electrons, 2s has 2 electrons, 2p has 6 electrons, 3s has 2 electrons, 3p has 6 electrons, 4s has 2 electrons, 3d has 4 electrons, 4p has 6 electrons, 5s has 2 electrons, 4d has 2 electrons.

Step2: Sum up electrons

$2 + 2+6 + 2+6 + 2+4 + 6+2 + 2=34$

Step3: Identify element

The element with 34 electrons is Selenium (Se).

Answer:

Se