QUESTION IMAGE
Question
part e. complete the following table: assume all atoms are neutral. isotope symbol nuclear symbol mass number number of protons number of neutrons number of electrons atomic number carbon - 12 12c 12 6 6 6 6 argon - 40 1840ar 40 18 22 18 18 iodine - 128 53128i 128 53 75 53 53 nickel - 60 2860ni 60 28 32 28 28 argon - 34 1834ar 34 16 21 19 14 13
Step1: Recall atomic - related concepts
For a neutral atom, the number of protons = number of electrons = atomic number. The mass number = number of protons+number of neutrons.
Step2: Analyze argon - 34 row
The atomic number of argon is 18. Given the mass number is 34 and number of protons is 16 (which is incorrect as atomic number of Ar is 18). Assuming the correct atomic number (number of protons) is 18, number of neutrons = mass number - number of protons = 34 - 18=16, number of electrons = number of protons = 18.
Step3: Analyze the row with number of electrons = 21 and atomic number = 19
Number of protons = atomic number = 19. Since it is a neutral atom, number of electrons = 19. Mass number = number of protons + number of neutrons = 19+21 = 40. The element with atomic number 19 is potassium (K), and the nuclear symbol is $_{19}^{40}K$.
Step4: Analyze the row with number of electrons = 13 and number of neutrons = 14
Number of protons = number of electrons = 13 (for neutral atom). Atomic number = 13. The element is aluminum (Al). Mass number = number of protons+number of neutrons = 13 + 14=27. The nuclear symbol is $_{13}^{27}Al$.
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| isotope symbol | nuclear symbol | mass number | number of protons | number of neutrons | number of electrons | atomic number |
|---|---|---|---|---|---|---|
| argon - 40 | $_{18}^{40}Ar$ | 40 | 18 | 22 | 18 | 18 |
| iodine - 128 | $_{53}^{128}I$ | 128 | 53 | 75 | 53 | 53 |
| nickel - 60 | $_{28}^{60}Ni$ | 60 | 28 | 32 | 28 | 28 |
| argon - 34 | $_{18}^{34}Ar$ | 34 | 18 | 16 | 18 | 18 |
| potassium - 40 | $_{19}^{40}K$ | 40 | 19 | 21 | 19 | 19 |
| aluminum - 27 | $_{13}^{27}Al$ | 27 | 13 | 14 | 13 | 13 |