Question

part of one row of the periodic table is shown. which elements atoms have the greatest average number of neutrons? 50 sn tin 118.71 51 sb antimony 121.76 52 te tellurium 127.60 53 i iodine 126.90 tin (sn) antimony (sb) tellurium (te) iodine (i)

Explanation:

Step1: Recall neutron - proton relationship

The number of neutrons (N) is approximately the mass number (A) minus the atomic number (Z). The atomic number is given by the number above the element symbol in the periodic - table.

Step2: Calculate number of neutrons for Sn

For tin (Sn) with atomic number \(Z = 50\) and atomic mass \(A=118.71\), the approximate number of neutrons \(N_{Sn}\approx119 - 50=69\) (rounding the atomic mass to the nearest whole number).

Step3: Calculate number of neutrons for Sb

For antimony (Sb) with atomic number \(Z = 51\) and atomic mass \(A = 121.76\), the approximate number of neutrons \(N_{Sb}\approx122 - 51 = 71\) (rounding the atomic mass to the nearest whole number).

Step4: Calculate number of neutrons for Te

For tellurium (Te) with atomic number \(Z = 52\) and atomic mass \(A=127.60\), the approximate number of neutrons \(N_{Te}\approx128 - 52 = 76\) (rounding the atomic mass to the nearest whole number).

Step5: Calculate number of neutrons for I

For iodine (I) with atomic number \(Z = 53\) and atomic mass \(A = 126.90\), the approximate number of neutrons \(N_{I}\approx127 - 53 = 74\) (rounding the atomic mass to the nearest whole number).

Answer:

tellurium (Te)