Question

part 1 (1 point)
rus
ruthenium (ii) sulphide
part 2 (1 point)
pdcl₂
palladium(ii) chloride
part 3 (1 point)
ag₂o
silver (i) oxide
part 4 (1 point)
wo₃
part 5 (1 point)
pto₂
platinum(iv) oxide
1st attempt

Explanation:

Step1: Determine tungsten's oxidation state

In $WO_3$, oxygen has an oxidation - state of - 2. Let the oxidation state of tungsten be $x$. Using the rule that the sum of oxidation states in a neutral compound is 0, we have $x+3\times(- 2)=0$.

Step2: Solve for tungsten's oxidation state

$x - 6 = 0$, so $x = +6$.

Answer:

Tungsten(VI) oxide