Question

part 3 of 4
tebr₄
electron domain geometry: select
molecular geometry: select
part 4 of 4
sf₆
electron domain geometry: select
molecular geometry: select

Explanation:

Step1: Determine valence - electrons of central atom in TeBr₄

Tellurium (Te) is in Group 6A, so it has 6 valence electrons. There are 4 Br atoms, and each Br contributes 1 electron for bonding. The number of bonding pairs is 4. The number of lone - pairs on Te is $\frac{6 - 4}{2}=1$. The total number of electron domains is 4 (bonding) + 1 (lone - pair)=5.

Step2: Find electron - domain geometry of TeBr₄

With 5 electron domains, the electron - domain geometry is trigonal bipyramidal.

Step3: Determine molecular geometry of TeBr₄

Since there is 1 lone - pair, the molecular geometry is seesaw.

Step4: Determine valence - electrons of central atom in SF₆

Sulfur (S) is in Group 6A, so it has 6 valence electrons. There are 6 F atoms, and each F contributes 1 electron for bonding. The number of bonding pairs is 6 and the number of lone - pairs on S is $\frac{6 - 6}{2}=0$. The total number of electron domains is 6.

Step5: Find electron - domain geometry of SF₆

With 6 electron domains, the electron - domain geometry is octahedral.

Step6: Determine molecular geometry of SF₆

Since there are no lone - pairs, the molecular geometry is also octahedral.

Answer:

For TeBr₄:
Electron Domain Geometry: Trigonal bipyramidal
Molecular Geometry: Seesaw
For SF₆:
Electron Domain Geometry: Octahedral
Molecular Geometry: Octahedral