Question

part 1: unit quiz 2a - electronic structure
complete the table below by filling in the missing information. all elements in the table are neutral.
give the full electron configuration for elements with less than 18 electrons.
give the noble gas electron configuration for elements with more than 18 electrons.

element symbol	total number of electrons	electron configuration	number of valence electrons	lewis dot structure
		1s²2s²2p⁶3s²3p³
				•as•

Explanation:

Step1: Determine total electrons for Al

Al (aluminum) has an atomic number of 13. So the total number of electrons in a neutral Al atom is 13.

Step2: Write electron - configuration for Al

The electron - configuration of Al is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}\).

Step3: Find number of valence electrons for Al

The electrons in the outermost shell are valence electrons. For Al, the outermost shell is the 3rd shell (\(3s^{2}3p^{1}\)), so the number of valence electrons is 3.

Step4: Analyze the given electron - configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}\)

The sum of the electrons in this configuration is \(2 + 2+6 + 2+3=15\). The element with 15 electrons is P (phosphorus). The number of valence electrons for P is 5 (from \(3s^{2}3p^{3}\)).

Step5: Analyze the Lewis - dot structure \(\cdot\text{As}\cdot\)

As (arsenic) has an atomic number of 33. The number of valence electrons for As is 5. The total number of electrons in As is 33. The noble - gas electron - configuration for As is \([Ar]4s^{2}3d^{10}4p^{3}\).

Answer:

ELEMENT SYMBOL	TOTAL NUMBER OF ELECTRONS	ELECTRON CONFIGURATION	NUMBER OF VALENCE ELECTRONS	LEWIS DOT STRUCTURE
P	15	\(1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}\)	5	\(\cdot\text{P}\cdot\)
As	33	\([Ar]4s^{2}3d^{10}4p^{3}\)	5	\(\cdot\text{As}\cdot\)