Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

periodic table worksheet instructions: using the periodic table fill ou…

Question

periodic table worksheet
instructions: using the periodic table fill out the blanks in this table. assume all rows are for elements that are neutral and not ions.

element name | atomic symbol | atomic number | proton # | neutron # | electron # | mass # (amu)
carbon | c | 6 | 6 | 8 | 6 | 14
magnesium | mg | 12 | 12 | 12 | 12 | 24

31314031
zr4089
30303530
4298
w183
10571
959595243
cr27
838383209
909014290
md259
se
80
40405140

Explanation:

Response

To solve the periodic table worksheet, we use the following relationships for neutral atoms:

  • Atomic Number = Proton # = Electron #
  • Mass # (amu) = Proton # + Neutron #
Row 1: Carbon (C)

Step 1: Atomic Number (Z)

For neutral C, Atomic Number = Proton # = Electron #. From the table, Neutron # = 8, Mass # = 14.
Proton # = Mass # − Neutron # = \( 14 - 8 = 6 \). Thus, Atomic Number = 6, Electron # = 6.

Row 2: Magnesium (Mg)

Step 1: Proton #

Atomic Number = 12, so Proton # = 12, Electron # = 12.

Step 2: Neutron #

Mass # = 24, so Neutron # = \( 24 - 12 = 12 \).

Row 3: Element with Proton # = 31

Step 1: Atomic Number

Atomic Number = Proton # = 31, so Electron # = 31.

Step 2: Mass #

Mass # = Proton # + Neutron # = \( 31 + 40 = 71 \).
Element: Gallium (Ga) (Atomic Number 31).

Row 4: Zirconium (Zr)

Step 1: Proton #

Electron # = 40 (neutral), so Proton # = 40, Atomic Number = 40.

Step 2: Neutron #

Mass # = 89, so Neutron # = \( 89 - 40 = 49 \).

Row 5: Atomic Number = 30

Step 1: Proton #, Electron #

Proton # = 30, Electron # = 30.

Step 2: Mass #

Mass # = \( 30 + 35 = 65 \).
Element: Zinc (Zn) (Atomic Number 30).

Row 6: Proton # = 42

Step 1: Atomic Number, Electron #

Atomic Number = 42, Electron # = 42.

Step 2: Neutron #

Mass # = 98, so Neutron # = \( 98 - 42 = 56 \).
Element: Molybdenum (Mo) (Atomic Number 42).

Row 7: Tungsten (W)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 74 (W has Z=74), so Proton # = 74, Electron # = 74.

Step 2: Neutron #

Mass # = 183, so Neutron # = \( 183 - 74 = 109 \).

Row 8: Electron # = 71

Step 1: Proton #, Atomic Number

Proton # = 71, Atomic Number = 71.

Step 2: Mass #

Mass # = \( 71 + 105 = 176 \).
Element: Lutetium (Lu) (Atomic Number 71).

Row 9: Atomic Number = 95

Step 1: Electron #

Electron # = 95 (neutral).

Step 2: Neutron #

Mass # = 243, so Neutron # = \( 243 - 95 = 148 \).
Element: Americium (Am) (Atomic Number 95).

Row 10: Chromium (Cr)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 24 (Cr has Z=24), so Proton # = 24, Electron # = 24.

Step 2: Mass #

Mass # = \( 24 + 27 = 51 \).

Row 11: Atomic Number = 83

Step 1: Proton #, Electron #

Proton # = 83, Electron # = 83.

Step 2: Neutron #

Mass # = 209, so Neutron # = \( 209 - 83 = 126 \).
Element: Bismuth (Bi) (Atomic Number 83).

Row 12: Atomic Number = 90

Step 1: Proton #, Electron #

Proton # = 90, Electron # = 90.

Step 2: Mass #

Mass # = \( 90 + 142 = 232 \).
Element: Thorium (Th) (Atomic Number 90).

Row 13: Mendelevium (Md)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 101 (Md has Z=101), so Proton # = 101, Electron # = 101.

Step 2: Neutron #

Mass # = 259, so Neutron # = \( 259 - 101 = 158 \).

Row 14: Selenium (Se)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 34 (Se has Z=34), so Proton # = 34, Electron # = 34.

Step 2: Neutron #

Mass # = 80, so Neutron # = \( 80 - 34 = 46 \).

Row 15: Atomic Number = 40

Step 1: Element, Electron #

Element: Zirconium (Zr) (Z=40), Electron # = 40.

Step 2: Mass #

Mass # = \( 40 + 51 = 91 \).

Filled Table (Key Values):
Element NameAtomic SymbolAtomic NumberProton #Neutron #Electron #Mass # (amu)
MagnesiumMg1212121224

|…

Answer:

To solve the periodic table worksheet, we use the following relationships for neutral atoms:

  • Atomic Number = Proton # = Electron #
  • Mass # (amu) = Proton # + Neutron #
Row 1: Carbon (C)

Step 1: Atomic Number (Z)

For neutral C, Atomic Number = Proton # = Electron #. From the table, Neutron # = 8, Mass # = 14.
Proton # = Mass # − Neutron # = \( 14 - 8 = 6 \). Thus, Atomic Number = 6, Electron # = 6.

Row 2: Magnesium (Mg)

Step 1: Proton #

Atomic Number = 12, so Proton # = 12, Electron # = 12.

Step 2: Neutron #

Mass # = 24, so Neutron # = \( 24 - 12 = 12 \).

Row 3: Element with Proton # = 31

Step 1: Atomic Number

Atomic Number = Proton # = 31, so Electron # = 31.

Step 2: Mass #

Mass # = Proton # + Neutron # = \( 31 + 40 = 71 \).
Element: Gallium (Ga) (Atomic Number 31).

Row 4: Zirconium (Zr)

Step 1: Proton #

Electron # = 40 (neutral), so Proton # = 40, Atomic Number = 40.

Step 2: Neutron #

Mass # = 89, so Neutron # = \( 89 - 40 = 49 \).

Row 5: Atomic Number = 30

Step 1: Proton #, Electron #

Proton # = 30, Electron # = 30.

Step 2: Mass #

Mass # = \( 30 + 35 = 65 \).
Element: Zinc (Zn) (Atomic Number 30).

Row 6: Proton # = 42

Step 1: Atomic Number, Electron #

Atomic Number = 42, Electron # = 42.

Step 2: Neutron #

Mass # = 98, so Neutron # = \( 98 - 42 = 56 \).
Element: Molybdenum (Mo) (Atomic Number 42).

Row 7: Tungsten (W)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 74 (W has Z=74), so Proton # = 74, Electron # = 74.

Step 2: Neutron #

Mass # = 183, so Neutron # = \( 183 - 74 = 109 \).

Row 8: Electron # = 71

Step 1: Proton #, Atomic Number

Proton # = 71, Atomic Number = 71.

Step 2: Mass #

Mass # = \( 71 + 105 = 176 \).
Element: Lutetium (Lu) (Atomic Number 71).

Row 9: Atomic Number = 95

Step 1: Electron #

Electron # = 95 (neutral).

Step 2: Neutron #

Mass # = 243, so Neutron # = \( 243 - 95 = 148 \).
Element: Americium (Am) (Atomic Number 95).

Row 10: Chromium (Cr)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 24 (Cr has Z=24), so Proton # = 24, Electron # = 24.

Step 2: Mass #

Mass # = \( 24 + 27 = 51 \).

Row 11: Atomic Number = 83

Step 1: Proton #, Electron #

Proton # = 83, Electron # = 83.

Step 2: Neutron #

Mass # = 209, so Neutron # = \( 209 - 83 = 126 \).
Element: Bismuth (Bi) (Atomic Number 83).

Row 12: Atomic Number = 90

Step 1: Proton #, Electron #

Proton # = 90, Electron # = 90.

Step 2: Mass #

Mass # = \( 90 + 142 = 232 \).
Element: Thorium (Th) (Atomic Number 90).

Row 13: Mendelevium (Md)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 101 (Md has Z=101), so Proton # = 101, Electron # = 101.

Step 2: Neutron #

Mass # = 259, so Neutron # = \( 259 - 101 = 158 \).

Row 14: Selenium (Se)

Step 1: Atomic Number, Proton #, Electron #

Atomic Number = 34 (Se has Z=34), so Proton # = 34, Electron # = 34.

Step 2: Neutron #

Mass # = 80, so Neutron # = \( 80 - 34 = 46 \).

Row 15: Atomic Number = 40

Step 1: Element, Electron #

Element: Zirconium (Zr) (Z=40), Electron # = 40.

Step 2: Mass #

Mass # = \( 40 + 51 = 91 \).

Filled Table (Key Values):
Element NameAtomic SymbolAtomic NumberProton #Neutron #Electron #Mass # (amu)
MagnesiumMg1212121224
GalliumGa3131403171
ZirconiumZr4040494089
ZincZn3030353065
MolybdenumMo4242564298
TungstenW747410974183
LutetiumLu717110571176
AmericiumAm959514895243
ChromiumCr2424272451
BismuthBi838312683209
ThoriumTh909014290232
MendeleviumMd101101158101259
SeleniumSe3434463480
ZirconiumZr4040514091

(Note: For each row, use the relationships \( \text{Atomic Number} = \text{Proton \#} = \text{Electron \#} \) and \( \text{Mass \#} = \text{Proton \#} + \text{Neutron \#} \) to fill blanks.)