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Question
periodic table worksheet
instructions: using the periodic table fill out the blanks in this table. assume all rows are for elements that are neutral and not ions.
element name | atomic symbol | atomic number | proton # | neutron # | electron # | mass # (amu)
carbon | c | 6 | 6 | 8 | 6 | 14
magnesium | mg | 12 | 12 | 12 | 12 | 24
| 31 | 31 | 40 | 31 | ||
| zr | 40 | 89 | |||
| 30 | 30 | 35 | 30 | ||
| 42 | 98 | ||||
| w | 183 | ||||
| 105 | 71 | ||||
| 95 | 95 | 95 | 243 | ||
| cr | 27 | ||||
| 83 | 83 | 83 | 209 | ||
| 90 | 90 | 142 | 90 | ||
| md | 259 | ||||
| se | |||||
| 80 | |||||
| 40 | 40 | 51 | 40 |
To solve the periodic table worksheet, we use the following relationships for neutral atoms:
- Atomic Number = Proton # = Electron #
- Mass # (amu) = Proton # + Neutron #
Row 1: Carbon (C)
Step 1: Atomic Number (Z)
For neutral C, Atomic Number = Proton # = Electron #. From the table, Neutron # = 8, Mass # = 14.
Proton # = Mass # − Neutron # = \( 14 - 8 = 6 \). Thus, Atomic Number = 6, Electron # = 6.
Row 2: Magnesium (Mg)
Step 1: Proton #
Atomic Number = 12, so Proton # = 12, Electron # = 12.
Step 2: Neutron #
Mass # = 24, so Neutron # = \( 24 - 12 = 12 \).
Row 3: Element with Proton # = 31
Step 1: Atomic Number
Atomic Number = Proton # = 31, so Electron # = 31.
Step 2: Mass #
Mass # = Proton # + Neutron # = \( 31 + 40 = 71 \).
Element: Gallium (Ga) (Atomic Number 31).
Row 4: Zirconium (Zr)
Step 1: Proton #
Electron # = 40 (neutral), so Proton # = 40, Atomic Number = 40.
Step 2: Neutron #
Mass # = 89, so Neutron # = \( 89 - 40 = 49 \).
Row 5: Atomic Number = 30
Step 1: Proton #, Electron #
Proton # = 30, Electron # = 30.
Step 2: Mass #
Mass # = \( 30 + 35 = 65 \).
Element: Zinc (Zn) (Atomic Number 30).
Row 6: Proton # = 42
Step 1: Atomic Number, Electron #
Atomic Number = 42, Electron # = 42.
Step 2: Neutron #
Mass # = 98, so Neutron # = \( 98 - 42 = 56 \).
Element: Molybdenum (Mo) (Atomic Number 42).
Row 7: Tungsten (W)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 74 (W has Z=74), so Proton # = 74, Electron # = 74.
Step 2: Neutron #
Mass # = 183, so Neutron # = \( 183 - 74 = 109 \).
Row 8: Electron # = 71
Step 1: Proton #, Atomic Number
Proton # = 71, Atomic Number = 71.
Step 2: Mass #
Mass # = \( 71 + 105 = 176 \).
Element: Lutetium (Lu) (Atomic Number 71).
Row 9: Atomic Number = 95
Step 1: Electron #
Electron # = 95 (neutral).
Step 2: Neutron #
Mass # = 243, so Neutron # = \( 243 - 95 = 148 \).
Element: Americium (Am) (Atomic Number 95).
Row 10: Chromium (Cr)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 24 (Cr has Z=24), so Proton # = 24, Electron # = 24.
Step 2: Mass #
Mass # = \( 24 + 27 = 51 \).
Row 11: Atomic Number = 83
Step 1: Proton #, Electron #
Proton # = 83, Electron # = 83.
Step 2: Neutron #
Mass # = 209, so Neutron # = \( 209 - 83 = 126 \).
Element: Bismuth (Bi) (Atomic Number 83).
Row 12: Atomic Number = 90
Step 1: Proton #, Electron #
Proton # = 90, Electron # = 90.
Step 2: Mass #
Mass # = \( 90 + 142 = 232 \).
Element: Thorium (Th) (Atomic Number 90).
Row 13: Mendelevium (Md)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 101 (Md has Z=101), so Proton # = 101, Electron # = 101.
Step 2: Neutron #
Mass # = 259, so Neutron # = \( 259 - 101 = 158 \).
Row 14: Selenium (Se)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 34 (Se has Z=34), so Proton # = 34, Electron # = 34.
Step 2: Neutron #
Mass # = 80, so Neutron # = \( 80 - 34 = 46 \).
Row 15: Atomic Number = 40
Step 1: Element, Electron #
Element: Zirconium (Zr) (Z=40), Electron # = 40.
Step 2: Mass #
Mass # = \( 40 + 51 = 91 \).
Filled Table (Key Values):
| Element Name | Atomic Symbol | Atomic Number | Proton # | Neutron # | Electron # | Mass # (amu) |
|---|---|---|---|---|---|---|
| Magnesium | Mg | 12 | 12 | 12 | 12 | 24 |
|…
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To solve the periodic table worksheet, we use the following relationships for neutral atoms:
- Atomic Number = Proton # = Electron #
- Mass # (amu) = Proton # + Neutron #
Row 1: Carbon (C)
Step 1: Atomic Number (Z)
For neutral C, Atomic Number = Proton # = Electron #. From the table, Neutron # = 8, Mass # = 14.
Proton # = Mass # − Neutron # = \( 14 - 8 = 6 \). Thus, Atomic Number = 6, Electron # = 6.
Row 2: Magnesium (Mg)
Step 1: Proton #
Atomic Number = 12, so Proton # = 12, Electron # = 12.
Step 2: Neutron #
Mass # = 24, so Neutron # = \( 24 - 12 = 12 \).
Row 3: Element with Proton # = 31
Step 1: Atomic Number
Atomic Number = Proton # = 31, so Electron # = 31.
Step 2: Mass #
Mass # = Proton # + Neutron # = \( 31 + 40 = 71 \).
Element: Gallium (Ga) (Atomic Number 31).
Row 4: Zirconium (Zr)
Step 1: Proton #
Electron # = 40 (neutral), so Proton # = 40, Atomic Number = 40.
Step 2: Neutron #
Mass # = 89, so Neutron # = \( 89 - 40 = 49 \).
Row 5: Atomic Number = 30
Step 1: Proton #, Electron #
Proton # = 30, Electron # = 30.
Step 2: Mass #
Mass # = \( 30 + 35 = 65 \).
Element: Zinc (Zn) (Atomic Number 30).
Row 6: Proton # = 42
Step 1: Atomic Number, Electron #
Atomic Number = 42, Electron # = 42.
Step 2: Neutron #
Mass # = 98, so Neutron # = \( 98 - 42 = 56 \).
Element: Molybdenum (Mo) (Atomic Number 42).
Row 7: Tungsten (W)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 74 (W has Z=74), so Proton # = 74, Electron # = 74.
Step 2: Neutron #
Mass # = 183, so Neutron # = \( 183 - 74 = 109 \).
Row 8: Electron # = 71
Step 1: Proton #, Atomic Number
Proton # = 71, Atomic Number = 71.
Step 2: Mass #
Mass # = \( 71 + 105 = 176 \).
Element: Lutetium (Lu) (Atomic Number 71).
Row 9: Atomic Number = 95
Step 1: Electron #
Electron # = 95 (neutral).
Step 2: Neutron #
Mass # = 243, so Neutron # = \( 243 - 95 = 148 \).
Element: Americium (Am) (Atomic Number 95).
Row 10: Chromium (Cr)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 24 (Cr has Z=24), so Proton # = 24, Electron # = 24.
Step 2: Mass #
Mass # = \( 24 + 27 = 51 \).
Row 11: Atomic Number = 83
Step 1: Proton #, Electron #
Proton # = 83, Electron # = 83.
Step 2: Neutron #
Mass # = 209, so Neutron # = \( 209 - 83 = 126 \).
Element: Bismuth (Bi) (Atomic Number 83).
Row 12: Atomic Number = 90
Step 1: Proton #, Electron #
Proton # = 90, Electron # = 90.
Step 2: Mass #
Mass # = \( 90 + 142 = 232 \).
Element: Thorium (Th) (Atomic Number 90).
Row 13: Mendelevium (Md)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 101 (Md has Z=101), so Proton # = 101, Electron # = 101.
Step 2: Neutron #
Mass # = 259, so Neutron # = \( 259 - 101 = 158 \).
Row 14: Selenium (Se)
Step 1: Atomic Number, Proton #, Electron #
Atomic Number = 34 (Se has Z=34), so Proton # = 34, Electron # = 34.
Step 2: Neutron #
Mass # = 80, so Neutron # = \( 80 - 34 = 46 \).
Row 15: Atomic Number = 40
Step 1: Element, Electron #
Element: Zirconium (Zr) (Z=40), Electron # = 40.
Step 2: Mass #
Mass # = \( 40 + 51 = 91 \).
Filled Table (Key Values):
| Element Name | Atomic Symbol | Atomic Number | Proton # | Neutron # | Electron # | Mass # (amu) |
|---|---|---|---|---|---|---|
| Magnesium | Mg | 12 | 12 | 12 | 12 | 24 |
| Gallium | Ga | 31 | 31 | 40 | 31 | 71 |
| Zirconium | Zr | 40 | 40 | 49 | 40 | 89 |
| Zinc | Zn | 30 | 30 | 35 | 30 | 65 |
| Molybdenum | Mo | 42 | 42 | 56 | 42 | 98 |
| Tungsten | W | 74 | 74 | 109 | 74 | 183 |
| Lutetium | Lu | 71 | 71 | 105 | 71 | 176 |
| Americium | Am | 95 | 95 | 148 | 95 | 243 |
| Chromium | Cr | 24 | 24 | 27 | 24 | 51 |
| Bismuth | Bi | 83 | 83 | 126 | 83 | 209 |
| Thorium | Th | 90 | 90 | 142 | 90 | 232 |
| Mendelevium | Md | 101 | 101 | 158 | 101 | 259 |
| Selenium | Se | 34 | 34 | 46 | 34 | 80 |
| Zirconium | Zr | 40 | 40 | 51 | 40 | 91 |
(Note: For each row, use the relationships \( \text{Atomic Number} = \text{Proton \#} = \text{Electron \#} \) and \( \text{Mass \#} = \text{Proton \#} + \text{Neutron \#} \) to fill blanks.)