Question

phosphorus (p)
electron configuration: ____________
noble gas configuration (abbreviated): ____________
fluorine (f)
electron configuration: ____________
noble gas configuration (abbreviated): ____________

Explanation:

Step1: Recall atomic number of phosphorus

Phosphorus (P) has atomic number 15. Electrons are filled according to Aufbau - principle.

Step2: Fill electrons for phosphorus

1s is filled first with 2 electrons, then 2s with 2 electrons, 2p with 6 electrons, 3s with 2 electrons and 3p with 3 electrons. So electron - configuration of P is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$.

Step3: Write noble - gas configuration for phosphorus

The nearest noble gas before P is Ne. Ne has electron - configuration $1s^{2}2s^{2}2p^{6}$. So noble - gas configuration of P is $[Ne]3s^{2}3p^{3}$.

Step4: Recall atomic number of fluorine

Fluorine (F) has atomic number 9.

Step5: Fill electrons for fluorine

1s is filled with 2 electrons, 2s with 2 electrons and 2p with 5 electrons. So electron - configuration of F is $1s^{2}2s^{2}2p^{5}$.

Step6: Write noble - gas configuration for fluorine

The nearest noble gas before F is He. He has electron - configuration $1s^{2}$. So noble - gas configuration of F is $[He]2s^{2}2p^{5}$.

Answer:

Phosphorus:
Electron Configuration: $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$
Noble Gas Configuration (abbreviated): $[Ne]3s^{2}3p^{3}$
Fluorine:
Electron Configuration: $1s^{2}2s^{2}2p^{5}$
Noble Gas Configuration (abbreviated): $[He]2s^{2}2p^{5}$