Question

preparation of first diluted solutionmolarity of stock cuso₄ solution (m): 0.123volume of stock cuso₄ solution (ml): 10.0total volume of diluted cuso₄ solution (ml): 100.00molarity of diluted cuso₄ solution (m)preparation of second diluted solutionshow labels

Explanation:

Step1: Recall dilution formula

The dilution principle is $M_1V_1 = M_2V_2$, where $M_1$ = stock molarity, $V_1$ = stock volume, $M_2$ = diluted molarity, $V_2$ = diluted volume.

Step2: Plug in given values

Substitute $M_1=0.123\ M$, $V_1=10.0\ \text{mL}$, $V_2=100.00\ \text{mL}$ into the formula:
$0.123 \times 10.0 = M_2 \times 100.00$

Step3: Solve for $M_2$

Rearrange to isolate $M_2$:
$M_2 = \frac{0.123 \times 10.0}{100.00}$

Answer:

$0.0123\ M$