Question

protocol

1. your ta weighed out 1 g of lipase
2. your ta dissolved lipase in 0.05 l of water

prelab questions -11 (1 pt). determine how many ml are in 0.05 l of water.
0.05l $\frac{1000ml}{1l}$ = 50ml
determine the mass/volume percent (m/v%) of your lipase solution.
$\frac{m}{v}%=\frac{g of solute}{space solute takes up + ml solvent}$×100 1g lipase

Explanation:

Step1: Convert liters to milliliters

We know that 1 L = 1000 mL. So, to convert 0.05 L to mL, we use the conversion factor $\frac{1000\text{ mL}}{1\text{ L}}$.
$0.05\text{ L}\times\frac{1000\text{ mL}}{1\text{ L}} = 50\text{ mL}$

Step2: Calculate mass - volume percent

The formula for mass - volume percent ($m/v\%$) is $\frac{\text{mass of solute (g)}}{\text{volume of solution (mL)}}\times100$. The mass of lipase (solute) is 1 g and the volume of the solution (since the solute is dissolved in 0.05 L = 50 mL of water, assume volume of solution is 50 mL) is 50 mL.
$m/v\%=\frac{1\text{ g}}{50\text{ mL}}\times 100 = 2\%$

Answer:

The volume in mL is 50 mL and the mass - volume percent of the lipase solution is 2%.