Question

question 4 (10 points) what mass (in grams) corresponds to 4.50×10²³ atoms of zinc a 7.48×10⁻¹ b 25.8g c 39.2g d 740g

Explanation:

Step1: Recall Avogadro's number and Zn molar mass

Avogadro's number: $N_A = 6.022 \times 10^{23} \text{ atoms/mol}$, Molar mass of Zn: $M = 65.38 \text{ g/mol}$

Step2: Calculate moles of Zn

$$n = \frac{\text{Number of atoms}}{N_A} = \frac{4.50 \times 10^{23}}{6.022 \times 10^{23} \text{ mol}^{-1}} \approx 0.747 \text{ mol}$$

Step3: Calculate mass of Zn

$$m = n \times M = 0.747 \text{ mol} \times 65.38 \text{ g/mol} \approx 39.2 \text{ g}$$

Answer:

c. 39.2g