Question

question 15. when balancing the equation h3po4 + koh → k3po4 + h2o the coefficient for water is blank 1. enter your answer

Explanation:

Step1: Balance the chemical equation

The un - balanced equation is $H_3PO_4+KOH
ightarrow K_3PO_4 + H_2O$. First, balance the potassium ($K$) atoms. There are 3 $K$ atoms in $K_3PO_4$, so we need 3 moles of $KOH$. The equation becomes $H_3PO_4 + 3KOH
ightarrow K_3PO_4+H_2O$. Then, balance the hydrogen ($H$) and oxygen ($O$) atoms. On the left - hand side, we have $3 + 3=6$ hydrogen atoms and $4 + 3 = 7$ oxygen atoms. On the right - hand side, in $K_3PO_4$ we have 4 oxygen atoms. For the hydrogen atoms, in $H_2O$, to balance the 6 hydrogen atoms from the reactants, we need 3 moles of $H_2O$. The balanced equation is $H_3PO_4+3KOH
ightarrow K_3PO_4 + 3H_2O$.

Answer:

3