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question 18 (1 point) what is the ph of a 0.0001 m aqueous solution of hcl? 1 2 3 4
Step1: Recall pH formula
pH = -log[H⁺]
Step2: Determine [H⁺] for HCl
HCl is a strong - acid and dissociates completely in water. For 0.0001 M HCl, [H⁺]=0.0001 M = 1×10⁻⁴ M.
Step3: Calculate pH
pH=-log(1×10⁻⁴) = 4
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