Question

question 23 of 30 what is the balanced form of the chemical equation shown below? ca(oh)2(aq) + na2co3(aq) → caco3(s) + naoh(aq) a. ca(oh)2(aq) + na2co3(aq) → caco3(s) + 2naoh(aq) b. ca(oh)2(aq) + na2co3(aq) → caco3(s) + naoh(aq) c. 2ca(oh)2(aq) + na2co3(aq) → 2caco3(s) + 2naoh(aq) d. caoh(aq) + na2co3(aq) → caco3(s) + na2oh(aq)

Explanation:

Step1: Count atoms on reactant side

On the left - hand side, for the given equation $Ca(OH)_2(aq)+Na_2CO_3(aq)
ightarrow CaCO_3(s)+NaOH(aq)$, we have 1 Ca atom, 2 Na atoms, 1 C atom, 5 O atoms, and 2 H atoms.

Step2: Balance Na and H atoms

To balance the Na and H atoms, we need 2 moles of NaOH on the product side. So the balanced equation is $Ca(OH)_2(aq)+Na_2CO_3(aq)
ightarrow CaCO_3(s)+2NaOH(aq)$.

Answer:

A. $Ca(OH)_2(aq)+Na_2CO_3(aq)
ightarrow CaCO_3(s)+2NaOH(aq)$