Question

question 26
which of the following is an oxidation half - reaction?
fe3+ + e−→fe2+
sn2+→sn4+ + 2e−
cl2+2e−→2cl−
o2 + 4h+ + 4e−→2h2o
1 pts
question 27
which of the following is a reduction half - reaction?

Explanation:

Step1: Recall oxidation concept

Oxidation is loss of electrons.

Step2: Analyze each option

• $\ce{Fe^3+ + e-

ightarrow Fe^2+}$ is reduction as it gains an electron.

• $\ce{Sn^2+

ightarrow Sn^4+ + 2e-}$ is oxidation as tin - 2+ loses 2 electrons to form tin - 4+.

• $\ce{Cl2 + 2e-

ightarrow 2Cl-}$ is reduction as chlorine gains electrons.

• $\ce{O2 + 4H+ + 4e-

ightarrow 2H2O}$ is reduction as oxygen gains electrons.

Answer:

$\ce{Sn^2+
ightarrow Sn^4+ + 2e-}$