Question

question 27 (1 point) what is/are the carbonyl product(s) formed when the alcohol below is oxidized with k2cr2o7? oh h3c - ch2 - c - ch3 ch3 o h3c - ch2 - c - ch3 ch3 - ch2 c = c ch3 h ch3 o h3c - ch2 - c - oh

Explanation:

Step1: Identify the type of alcohol

The given alcohol is a tertiary alcohol since the carbon - OH group is attached to is bonded to three other carbon atoms.

Step2: Recall oxidation of alcohols

Tertiary alcohols do not undergo oxidation with oxidizing agents like $K_2Cr_2O_7$ because there is no hydrogen atom on the carbon bearing the - OH group that can be removed to form a carbon - oxygen double bond. So, no carbonyl products are formed.

Answer:

None of the above options are correct as no carbonyl products are formed.