Question

question 8 of 30
what is the mass of 2.25 moles of manganese(iv) sulfide (mns₂)?
the periodic table
a. 2.25 g
b. 1.35×10²⁴ g
c. 3.63×10²⁶ g
d. 268 g

Explanation:

Step1: Find molar mass of MnS₂

The molar mass of Mn (manganese) is approximately 54.94 g/mol and S (sulfur) is approximately 32.07 g/mol. For MnS₂, molar mass $M = 54.94+2\times32.07=54.94 + 64.14=119.08$ g/mol.

Step2: Calculate mass of 2.25 moles

We use the formula $m=n\times M$, where $n = 2.25$ moles and $M = 119.08$ g/mol. So $m=2.25\times119.08 = 267.93\approx268$ g.

Answer:

D. 268 g