Question

question 6 (1 point)
assign oxidation numbers to ch₃oh.
c - h - o -

Explanation:

Step1: Set rules for oxidation numbers

Hydrogen usually has an oxidation number of +1 in compounds, and oxygen usually has an oxidation number of -2 in compounds. Let the oxidation number of carbon in \(CH_{3}OH\) be \(x\).

Step2: Calculate oxidation number of carbon

The sum of oxidation numbers in a neutral compound is zero. In \(CH_{3}OH\), there is 1 carbon atom, 4 hydrogen atoms and 1 oxygen atom. So we have the equation \(x+(+ 1)\times4+(-2)=0\). Solving for \(x\): \(x + 4-2=0\), \(x=-2\).

Step3: Determine oxidation number of hydrogen

Hydrogen has an oxidation number of +1 as per the common - rule for non - metal hydrides.

Step4: Determine oxidation number of oxygen

Oxygen has an oxidation number of -2 as per the common - rule for compounds other than peroxides.

Answer:

C -2, H +1, O -2