Question

question 9 (1 point) listen which bond angle is the largest? a) h - si - h in sih4 b) f - s - f in sf6 c) o - c - s in cos d) o - c - o in co32- e) cl - c - cl in cocl2

Explanation:

Step1: Recall molecular geometries

Determine the molecular geometry of each species to find bond - angles.

Step2: Analyze \(SiH_4\)

\(SiH_4\) has a tetrahedral geometry. The \(H - Si - H\) bond angle is \(109.5^{\circ}\).

Step3: Analyze \(SF_6\)

\(SF_6\) has an octahedral geometry. The \(F - S - F\) bond angles are \(90^{\circ}\) and \(180^{\circ}\). The \(90^{\circ}\) angles are between equatorial - axial and axial - axial pairs, and the \(180^{\circ}\) is between opposite axial atoms.

Step4: Analyze \(COS\)

\(COS\) is a linear molecule. The \(O - C - S\) bond angle is \(180^{\circ}\).

Step5: Analyze \(CO_3^{2 -}\)

\(CO_3^{2 -}\) has a trigonal - planar geometry. The \(O - C - O\) bond angle is \(120^{\circ}\).

Step6: Analyze \(COCl_2\)

\(COCl_2\) has a trigonal - planar geometry. The \(Cl - C - Cl\) bond angle is less than \(120^{\circ}\) due to the presence of the double - bonded oxygen which has greater repulsion than the single - bonded chlorine atoms.

Answer:

C. \(O - C - S\) in \(COS\)