Question

question 1 (1 point) listen which is true of an atom of \\(_{27}^{67}\text{co}\\)? select all that apply. a) it has 67 neutrons. b) it has the same mass as \\(_{24}^{67}\text{cr}\\). c) it has 40 electrons. d) it has 27 protons. e) it has more mass than \\(_{29}^{65}\text{cu}\\).

Explanation:

Step1: Identify proton count

For an atom $_Z^A\text{X}$, $Z$ = proton count. For $_{27}^{67}\text{Co}$, $Z=27$, so protons = 27.

Step2: Calculate neutron count

Neutrons = $A-Z$. $67-27=40$, so neutrons = 40.

Step3: Determine electron count

Neutral atom has electrons = protons = 27.

Step4: Compare mass numbers

$_{27}^{67}\text{Co}$ has $A=67$; $_{24}^{67}\text{Cr}$ has $A=67$ (same mass number, so same approximate mass). $_{29}^{65}\text{Cu}$ has $A=65 < 67$, so $_{27}^{67}\text{Co}$ has more mass.

Answer:

b) It has the same mass as $_{24}^{67}\text{Cr}$.
d) It has 27 protons.
e) It has more mass than $_{29}^{65}\text{Cu}$.