Question

question 2 1 pts what is the noble gas configuration of phosphorus? ne 3s² 2p³ ne 3s² 3p³ ne 3s² 4p³ ne 2s² 2p³

Explanation:

To determine the noble gas configuration of phosphorus (P, atomic number 15), we first note that neon (Ne, atomic number 10) is the noble gas with a lower atomic number than P. The electron configuration of Ne is $1s^2 2s^2 2p^6$. For P, after the Ne core, we fill the next energy levels. The electron configuration of P is $1s^2 2s^2 2p^6 3s^2 3p^3$. So the noble gas configuration (using Ne as the core) is $[Ne] 3s^2 3p^3$. Let's analyze the options:

• $[Ne] 3s^2 2p^3$: Incorrect, as 2p is filled before Ne (Ne has $2p^6$), and after Ne we move to n=3.
• $[Ne] 3s^2 3p^3$: Correct, as it follows the Ne core with the remaining electrons in 3s and 3p.
• $[Ne] 3s^2 4p^3$: Incorrect, as we don't jump to n=4 after Ne; we fill n=3 first.
• $[Ne] 2s^2 2p^3$: Incorrect, as 2s and 2p are part of the Ne core (Ne has $2s^2 2p^6$), so we don't include them again after Ne.

Answer:

B. $[Ne] 3s^2 3p^3$ (assuming the second option is labeled B; if the original labels were different, adjust the label but keep the configuration. From the image, the selected option is $[Ne] 3s^2 3p^3$, so the correct answer is the option with $[Ne] 3s^2 3p^3$)