Question

rank the bonds in the two molecules shown in order of increasing polarity. (electronegativity values are: c, 2.5; f, 4.0; h, 2.1; o, 3.5) covalent bond (4 items) (drag and drop into the appropriate area) c - f o - h c - h relative polarity most polar 1

Explanation:

Step1: Calculate electronegativity difference for C - H

The electronegativity of C is 2.5 and of H is 2.1. The difference $\Delta\chi_{C - H}=|2.5 - 2.1|= 0.4$.

Step2: Calculate electronegativity difference for O - H

The electronegativity of O is 3.5 and of H is 2.1. The difference $\Delta\chi_{O - H}=|3.5 - 2.1| = 1.4$.

Step3: Calculate electronegativity difference for C - F

The electronegativity of C is 2.5 and of F is 4.0. The difference $\Delta\chi_{C - F}=|4.0 - 2.5|=1.5$.

Step4: Rank the bonds

Since $0.4<1.4<1.5$, the order of increasing polarity is C - H < O - H < C - F.

Answer:

C - H, O - H, C - F