Question

a \generic\ reactoin has the balanced equation: 3a + 4b --> c + 5d. if you have 0.25 mol of a, how many mol of d are produced (assume excess b)? 0.85 0.42 0.15 0.25

Explanation:

Step1: Identify mole - ratio

From the balanced equation $3A + 4B
ightarrow C + 5D$, the mole - ratio of $A$ to $D$ is $n_A:n_D=3:5$.

Step2: Set up proportion

Let $x$ be the number of moles of $D$ produced. We have the proportion $\frac{n_A}{n_D}=\frac{3}{5}$, where $n_A = 0.25$ mol. So, $\frac{0.25}{x}=\frac{3}{5}$.

Step3: Solve for $x$

Cross - multiply to get $3x=0.25\times5$. Then $3x = 1.25$, and $x=\frac{1.25}{3}\approx0.42$ mol.

Answer:

0.42