Question

read each description in the first column of the table below. if any chemical element with atomic number of 92 or less matches the description, check yes and enter the chemical symbol of an element that matches. otherwise check no in the second column.

description	does any element with z ≤ 92 match the description?	if you checked yes, give the symbol of an element with z ≤ 92 that matches.
a nonmetal in group 6a.	☐ yes ☐ no
an element in the nitrogen family with a higher atomic number than nitrogen.	☐ yes ☐ no
a transition element in period 5.	☐ yes ☐ no

Explanation:

1. An element in Period 2 and Group 1A.

Step1: Recall Period and Group definitions.

Period 2 has elements with \( n = 2 \) (principal quantum number), Group 1A (alkali metals) has 1 valence electron. In Period 2, Group 1A element is Lithium? Wait, no: Period 1: H, He; Period 2: Li (Group 1A), Be (2A), B (13), C (14), N (15), O (16), F (17), Ne (18). Wait, Group 1A in Period 2: Li? Wait, Li is Period 2? No, Li is Period 2? Wait, Li has electron configuration \( 1s^2 2s^1 \), so \( n = 2 \), so Period 2. Wait, but Group 1A: Li is in Group 1A, Period 2? Wait, no, Period 1: H, He; Period 2: Li (Group 1), Be (2), B (13), C (14), N (15), O (16), F (17), Ne (18). So Li is Period 2, Group 1A. But wait, H is Period 1, Group 1A. So for Period 2, Group 1A: Li (Li). But wait, atomic number of Li is 3, which is \( \leq 92 \). So answer is Yes, and symbol Li. Wait, no: Wait, Period 2: elements from atomic number 3 (Li) to 10 (Ne). Group 1A: Li (3), Na (11, Period 3), etc. So Period 2, Group 1A: Li. So:

Step2: Determine the element.

Period 2 (n=2), Group 1A (1 valence electron). Element: Li (Lithium), atomic number 3 \( \leq 92 \). So "Does any element with Z ≤ 92 match?" Yes. Symbol: Li.

2. A nonmetal in Group 6A.

Step1: Recall Group 6A elements.

Group 6A (chalcogens): O, S, Se, Te, Po. Nonmetals: O, S, Se (Se is a metalloid? Wait, O and S are nonmetals, Se is a metalloid, Te is a metalloid, Po is a metal. So O (atomic 8), S (16) are nonmetals in Group 6A, Z ≤ 92. So "Does any element with Z ≤ 92 match?" Yes. Symbol: O (or S, Se). Let's take O.

Step2: Identify nonmetal in Group 6A.

Group 6A: O (nonmetal), Z=8 ≤92. So Yes, symbol O (or S, etc.).

3. An element in the nitrogen family with a higher atomic number than nitrogen.

Step1: Recall nitrogen family (Group 15).

Nitrogen (N, Z=7) is in Group 15. Other Group 15 elements: P (Z=15), As (33), Sb (51), Bi (83), Mc (115, but Z>92). So P, As, Sb, Bi have Z >7 and Z ≤92. So "Does any element with Z ≤92 match?" Yes. Symbol: P (or As, Sb, Bi). Let's take P.

Step2: Find Group 15 element > N's Z.

Nitrogen Z=7. Group 15 elements: P (15), As (33), Sb (51), Bi (83) have Z>7 and ≤92. So Yes, symbol P (e.g.).

4. A transition element in Period 5.

Answer:

s for each row:

1. An element in Period 2 and Group 1A:

Does any element with Z ≤ 92 match? $\boldsymbol{\text{Yes}}$
Symbol: $\boldsymbol{\text{Li}}$

1. A nonmetal in Group 6A:

Does any element with Z ≤ 92 match? $\boldsymbol{\text{Yes}}$
Symbol: $\boldsymbol{\text{O}}$ (or S, Se)

1. An element in the nitrogen family with a higher atomic number than nitrogen:

Does any element with Z ≤ 92 match? $\boldsymbol{\text{Yes}}$
Symbol: $\boldsymbol{\text{P}}$ (or As, Sb, Bi)

1. A transition element in Period 5:

Does any element with Z ≤ 92 match? $\boldsymbol{\text{Yes}}$
Symbol: $\boldsymbol{\text{Y}}$ (or Zr, Nb, etc.)