Question

the reduction half - reaction shows the need for two more oxygen atoms on the product side. will you add water or hydroxide to the product side?\\(\ce{mno^-_{4}} \
ightarrow \ce{mno_{2}} + ?\\)\
a. water\
b. hydroxide\
enter the answer choice letter.

Explanation:

, but the option is hydroxide (B) as a species. If we add water (A), we need 2 water molecules to get 2 O, but the option is water as a species. So maybe the question is considering that in basic solution, we add \(\ce{OH^{-}}\) to the product side, so the answer is B. So I think the correct answer is B.

Answer:

B. hydroxide