Question

rubidium has an atomic number of 37 and a mass number of 85. how many protons, neutrons, and electrons does an ion of rubidium with a 1+ charge have? (1 point) o 37 protons, 48 neutrons, 36 electrons o 37 protons, 48 neutrons, 38 electrons o 48 protons, 37 neutrons, 38 electrons o 48 protons, 37 neutrons, 36 electrons

Explanation:

Step1: Recall atomic - related concepts

The atomic number (Z) is equal to the number of protons. Given that the atomic number of rubidium is 37, the number of protons is 37.

Step2: Calculate the number of neutrons

The mass number (A) is the sum of protons and neutrons. Given A = 85 and Z = 37, the number of neutrons \(n=A - Z=85 - 37 = 48\).

Step3: Determine the number of electrons in a + 1 ion

In a neutral atom, the number of electrons is equal to the number of protons. For a \(Rb^+\) ion with a + 1 charge, it has lost one electron. So the number of electrons is \(37-1 = 36\).

Answer:

37 protons, 48 neutrons, and 36 electrons