Question

select all the correct answers.
based on the reactivities of the elements involved, which reactions will form products that are more stable than the reactants?
2lif + cl₂ → 2licl + f₂
2lii + cl₂ → 2licl + i₂
2licl + br₂ → 2libr + cl₂
2libr + f₂ → 2lif + br₂
2libr + i₂ → 2lii + br₂

Explanation:

To solve this, we use the reactivity of halogens (group 17 elements). Halogens are more reactive as we go up the group (F > Cl > Br > I). A more reactive halogen can displace a less reactive halogen from its salt. Stable products form when a more reactive halogen displaces a less reactive one (since the resulting compounds are more stable due to stronger bonds or more favorable electron configurations).

Analyzing each reaction:

Reaction 1: \( \boldsymbol{2\text{LiF} + \text{Cl}_2

ightarrow 2\text{LiCl} + \text{F}_2} \)
F is more reactive than Cl (F > Cl). So Cl₂ (less reactive) cannot displace F⁻ from LiF. This reaction does not occur, and products are not more stable.

Reaction 2: \( \boldsymbol{2\text{LiI} + \text{Cl}_2

ightarrow 2\text{LiCl} + \text{I}_2} \)
Cl is more reactive than I (Cl > I). So Cl₂ (more reactive) displaces I⁻ from LiI. The products (LiCl, I₂) are more stable because Cl forms a stronger bond with Li than I does, and I₂ is a stable diatomic molecule.

Reaction 3: \( \boldsymbol{2\text{LiCl} + \text{Br}_2

ightarrow 2\text{LiBr} + \text{Cl}_2} \)
Cl is more reactive than Br (Cl > Br). So Br₂ (less reactive) cannot displace Cl⁻ from LiCl. This reaction does not occur, and products are not more stable.

Reaction 4: \( \boldsymbol{2\text{LiBr} + \text{F}_2

ightarrow 2\text{LiF} + \text{Br}_2} \)
F is more reactive than Br (F > Br). So F₂ (more reactive) displaces Br⁻ from LiBr. The products (LiF, Br₂) are more stable because F forms a much stronger bond with Li than Br does, and Br₂ is a stable diatomic molecule.

Reaction 5: \( \boldsymbol{2\text{LiBr} + \text{I}_2

ightarrow 2\text{LiI} + \text{Br}_2} \)
Br is more reactive than I (Br > I). So I₂ (less reactive) cannot displace Br⁻ from LiBr. This reaction does not occur, and products are not more stable.

Answer:

The correct reactions are:

• \( 2\text{LiI} + \text{Cl}_2

ightarrow 2\text{LiCl} + \text{I}_2 \)

• \( 2\text{LiBr} + \text{F}_2

ightarrow 2\text{LiF} + \text{Br}_2 \)

(In boxed form for the selected options, assuming the checkboxes correspond to these two reactions.)