Question

a solution of hcl has h⁺ = 0.01 m. what is the ph of this solution? use ph = -logh₃o⁺.
○ -2
○ -1
○ 1
○ 2

Explanation:

Step1: Identify the formula

We use the formula for pH: $pH = -\log[H_3O^+]$. In an HCl solution, $[H^+] = [H_3O^+]$, and we know $[H^+] = 0.01\ M$.

Step2: Substitute the value into the formula

First, rewrite $0.01$ in scientific notation: $0.01 = 1\times10^{-2}$. Then substitute into the pH formula: $pH = -\log(1\times10^{-2})$.

Step3: Calculate the logarithm

Using the property of logarithms $\log(a\times10^b)=\log(a)+b$ (here $a = 1$, $b=-2$), so $\log(1\times10^{-2})=\log(1)+(-2)=0 - 2=-2$. Then $pH=-(-2)=2$.

Answer:

2