sulfuryl chloride is a substance used to make chemicals for killing insects. it breaks down over time into sulfur dioxide and chlorine gas. consider the following reaction: some amount of sulfuryl chloride (so₂cl₂) breaks down to produce 2 molecules of sulfur dioxide (so₂) and 2 molecules of chlorine (cl₂). complete the table below. chemical element | number of atoms in the reaction o s cl during this reaction, how many molecules of sulfuryl chloride (so₂cl₂) react?

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Accepted Answer

### Part 1: Completing the table (for O, S, Cl atoms)
#### Step 1: Analyze Oxygen (O) atoms
- From $ SO_2 $: Each $ SO_2 $ has 2 O atoms, and there are 2 $ SO_2 $ molecules. So O atoms from $ SO_2 $: $ 2 \times 2 = 4 $.
- $ SO_2Cl_2 $ and $ Cl_2 $ have no O atoms. So total O atoms: $ 4 $.

#### Step 2: Analyze Sulfur (S) atoms
- From $ SO_2 $: Each $ SO_2 $ has 1 S atom, 2 $ SO_2 $ molecules. So S atoms from $ SO_2 $: $ 2 \times 1 = 2 $.
- From $ SO_2Cl_2 $: Let the number of $ SO_2Cl_2 $ be $ x $. Each $ SO_2Cl_2 $ has 1 S atom. By conservation of S, $ x \times 1 = 2 $, so $ x = 2 $ (we'll use this for S count too: $ 2 \times 1 = 2 $).

#### Step 3: Analyze Chlorine (Cl) atoms
- From $ Cl_2 $: Each $ Cl_2 $ has 2 Cl atoms, 2 $ Cl_2 $ molecules. So Cl atoms from $ Cl_2 $: $ 2 \times 2 = 4 $.
- From $ SO_2Cl_2 $: Each $ SO_2Cl_2 $ has 2 Cl atoms, and we found $ x = 2 $ $ SO_2Cl_2 $ molecules. So Cl atoms from $ SO_2Cl_2 $: $ 2 \times 2 = 4 $ (matches conservation).

### Part 2: Number of $ SO_2Cl_2 $ molecules
#### Step 1: Use conservation of S (or Cl, O)
- For S: Each $ SO_2Cl_2 $ has 1 S, each $ SO_2 $ has 1 S. There are 2 $ SO_2 $ molecules, so S atoms from $ SO_2 $ is 2. Thus, $ SO_2Cl_2 $ must provide 2 S atoms. Since each $ SO_2Cl_2 $ has 1 S, number of $ SO_2Cl_2 $ molecules is $ \frac{2}{1} = 2 $.

### Table Completion:
| Chemical element | Number of atoms in the reaction |
|------------------|---------------------------------|
| O                | $ 4 $                         |
| S                | $ 2 $                         |
| Cl               | $ 4 $                         |

### Number of $ SO_2Cl_2 $ molecules:
The number of $ SO_2Cl_2 $ molecules that react is $ \boldsymbol{2} $.

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QUESTION IMAGE

Question

Explanation:

Part 1: Completing the table (for O, S, Cl atoms)

Step 1: Analyze Oxygen (O) atoms

Step 2: Analyze Sulfur (S) atoms

Step 3: Analyze Chlorine (Cl) atoms

Part 2: Number of \( SO_2Cl_2 \) molecules

Step 1: Use conservation of S (or Cl, O)

Table Completion:

Number of \( SO_2Cl_2 \) molecules:

Answer: