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Question
synthesis - what can we take away from all these patterns on the periodic table? 1. noble gases have a full outer shell of electrons. this seems to be a preferred situation for electrons. how can we tell this? noble gas by name, noble gas symbol, # protons and # electrons it has. 2. the alkali metals have 1 outer shell electron, and when they lose their 1 outer electron, become _ ions. alkali metals, alkali ion symbol with the charge it typically makes, # protons and #electrons in the ion. 3. the alkaline earth metals have 2 valence (outer shell) electrons and when they lose their 2 valence electrons, they’re _ ions. alkaline earth metal, alkaline earth ion symbol with the charge it makes, # protons and #electrons in the ion. 4. the halogens are only 1 e - away from the ideal number of valence electrons that the noble gasses have. what kind of ions will they form to be like the noble gasses? halogen, halogen ion symbol makes as an ion, #protons and #electrons in the ion
Step1: Recall noble - gas information
Noble gases include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn). Their symbols are He, Ne, Ar, Kr, Xe, Rn respectively. The number of protons and electrons for each: He has 2 protons and 2 electrons; Ne has 10 protons and 10 electrons; Ar has 18 protons and 18 electrons; Kr has 36 protons and 36 electrons; Xe has 54 protons and 54 electrons; Rn has 86 protons and 86 electrons.
Step2: Analyze alkali - metal ions
Alkali metals (lithium - Li, sodium - Na, potassium - K, rubidium - Rb, cesium - Cs, francium - Fr) lose one electron to form cations. For example, Li forms $Li^+$, with 3 protons and 2 electrons; Na forms $Na^+$, with 11 protons and 10 electrons.
Step3: Analyze alkaline - earth - metal ions
Alkaline earth metals (beryllium - Be, magnesium - Mg, calcium - Ca, strontium - Sr, barium - Ba, radium - Ra) lose two electrons to form cations. For example, Mg forms $Mg^{2 + }$, with 12 protons and 10 electrons.
Step4: Analyze halogen ions
Halogens (fluorine - F, chlorine - Cl, bromine - Br, iodine - I, astatine - At) gain one electron to form anions. For example, F forms $F^-$, with 9 protons and 10 electrons.
| Noble gas by name | Noble gas symbol | # protons and # electrons it has |
|---|---|---|
| Neon | Ne | 10 protons, 10 electrons |
| Argon | Ar | 18 protons, 18 electrons |
| Krypton | Kr | 36 protons, 36 electrons |
| Xenon | Xe | 54 protons, 54 electrons |
| Radon | Rn | 86 protons, 86 electrons |
| Alkali metals | Alkali ion symbol with the charge it typically makes | # protons and #electrons in the ion |
|---|---|---|
| Sodium | $Na^+$ | 11 protons, 10 electrons |
| Potassium | $K^+$ | 19 protons, 18 electrons |
| Rubidium | $Rb^+$ | 37 protons, 36 electrons |
| Cesium | $Cs^+$ | 55 protons, 54 electrons |
| Francium | $Fr^+$ | 87 protons, 86 electrons |
| Alkaline earth metal | Alkaline earth ion symbol with the charge it makes | # protons and #electrons in the ion |
|---|---|---|
| Magnesium | $Mg^{2+}$ | 12 protons, 10 electrons |
| Calcium | $Ca^{2+}$ | 20 protons, 18 electrons |
| Strontium | $Sr^{2+}$ | 38 protons, 36 electrons |
| Barium | $Ba^{2+}$ | 56 protons, 54 electrons |
| Radium | $Ra^{2+}$ | 88 protons, 86 electrons |
| halogen | Halogen ION symbol makes as an ION | #protons and #electrons in the ion |
|---|---|---|
| Chlorine | $Cl^-$ | 17 protons, 18 electrons |
| Bromine | $Br^-$ | 35 protons, 36 electrons |
| Iodine | $I^-$ | 53 protons, 54 electrons |
| Astatine | $At^-$ | 85 protons, 86 electrons |
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