Question

take quiz exit question 4 1 pts true or false: molecules with the formulas ch₃coh₂cooh and c₃h₆o₂ could be structural isomers. true false question 5 1 pts true or false: molecules must have a double bond to be cis-trans isomers. true false

Explanation:

Question 4

To determine if the two molecules can be structural isomers, we first check their molecular formulas. Let's count the atoms in \( \text{CH}_3\text{COH}_2\text{COOH} \). Wait, maybe there's a typo (should it be \( \text{CH}_3\text{CH}_2\text{COOH} \)? But as given, let's count: C: Let's see, \( \text{CH}_3 \) (1 C), \( \text{COH}_2 \) (1 C), \( \text{COOH} \) (1 C) → total C: 3? Wait, no, maybe the formula is miswritten. Wait, \( \text{C}_3\text{H}_6\text{O}_2 \) has 3 C, 6 H, 2 O. Let's check the first formula: \( \text{CH}_3\text{COH}_2\text{COOH} \) – let's count C: \( \text{CH}_3 \) (1), \( \text{COH}_2 \) (1), \( \text{COOH} \) (1) → 3 C. H: \( \text{CH}_3 \) (3), \( \text{COH}_2 \) (2), \( \text{COOH} \) (1) → 3+2+1=6? Wait, no, \( \text{COOH} \) has 1 H? Wait, \( \text{COOH} \) is carboxyl, which has one H? Wait, no, \( \text{CH}_3\text{CH}_2\text{COOH} \) (propanoic acid) has formula \( \text{C}_3\text{H}_6\text{O}_2 \). But the given first formula is \( \text{CH}_3\text{COH}_2\text{COOH} \) – maybe a typo, but if we count, let's see: C: 3, H: let's re-express the formula. Maybe it's \( \text{CH}_3\text{CH(OH)COOH} \)? No, the user wrote \( \text{CH}_3\text{COH}_2\text{COOH} \). Wait, maybe it's a mistake, but let's check the number of atoms. \( \text{C}_3\text{H}_6\text{O}_2 \) has 3 C, 6 H, 2 O. The first formula: \( \text{CH}_3\text{COH}_2\text{COOH} \) – let's count C: \( \text{CH}_3 \) (1), \( \text{COH}_2 \) (1), \( \text{COOH} \) (1) → 3 C. H: \( \text{CH}_3 \) (3), \( \text{COH}_2 \) (2), \( \text{COOH} \) (1) → 3+2+1=6? O: \( \text{COH}_2 \) (1), \( \text{COOH} \) (2) → 3 O. Wait, that's 3 O, but \( \text{C}_3\text{H}_6\text{O}_2 \) has 2 O. So the molecular formulas are different (first has 3 O, second has 2 O). Structural isomers must have the same molecular formula. So the answer is False.

Cis - trans isomers (geometric isomers) require a double bond (or a ring structure with restricted rotation) where the groups attached to the carbons of the double bond are different. The double bond restricts rotation, allowing for different arrangements (cis: same side, trans: opposite side). So molecules must have a double bond (or a ring with restricted rotation, but the most common case is a double bond) to exhibit cis - trans isomerism. So the statement is True.

Answer:

False

Question 5