Question

there are six times as many whitetail deer as mule deer in the woods. if jacob gets one deer in the woods, what is the probability that jacob gets a mule deer? a. \\(\frac{1}{7}\\) b. \\(\frac{1}{6}\\) c. \\(\frac{6}{7}\\) d. \\(\frac{1}{8}\\)

Explanation:

Step1: Define Variables

Let the number of mule deer be \( x \). Then the number of whitetail deer is \( 6x \) (since there are six times as many whitetail deer as mule deer).

Step2: Calculate Total Number of Deer

The total number of deer in the woods is the sum of mule deer and whitetail deer. So, total deer \( = x + 6x = 7x \).

Step3: Calculate Probability of Getting a Mule Deer

The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes. Here, the favorable outcome (getting a mule deer) is \( x \), and the total number of outcomes (total deer) is \( 7x \). So the probability \( P(\text{mule deer})=\frac{x}{7x} \). The \( x \) cancels out (assuming \( x
eq0 \), which makes sense because there are deer), so \( P(\text{mule deer}) = \frac{1}{7} \).

Answer:

A. \(\frac{1}{7}\)