Question

total number of fe atoms in this sample of 122 g fe2o3 is is 9.15x 10^23
true
false
question 4 of 4

Explanation:

Step1: Calculate molar mass of Fe₂O₃

The molar mass of Fe is approximately 55.85 g/mol and O is 16 g/mol. For Fe₂O₃, $M = 2\times55.85+3\times16=159.7$ g/mol.

Step2: Calculate number of moles of Fe₂O₃

$n=\frac{m}{M}$, where $m = 122$ g and $M = 159.7$ g/mol. So $n=\frac{122}{159.7}\approx0.764$ mol.

Step3: Calculate number of moles of Fe atoms

In 1 mole of Fe₂O₃, there are 2 moles of Fe atoms. So moles of Fe atoms in 0.764 mol of Fe₂O₃ is $n_{Fe}=2\times0.764 = 1.528$ mol.

Step4: Calculate number of Fe atoms

Using Avogadro's number $N_A = 6.022\times10^{23}$ atoms/mol, the number of Fe atoms $N=n_{Fe}\times N_A=1.528\times6.022\times10^{23}\approx9.2\times 10^{23}$ atoms.

Answer:

False