Question

type the correct answer in each box. which chemical symbols will complete the equation for this single displacement reaction? 2nabr + cl₂ → 2 □ □ + □₂

Explanation:

Step1: Recall single displacement reaction rules

In a single displacement reaction, a more reactive element displaces a less reactive element from its compound. For halogens (Group 17), the reactivity decreases down the group: \( \text{Cl} > \text{Br} > \text{I} \). So, chlorine (\( \text{Cl}_2 \)) can displace bromine (\( \text{Br}^- \)) from sodium bromide (\( \text{NaBr} \)).

Step2: Determine products

The reaction is \( 2\text{NaBr} + \text{Cl}_2
ightarrow 2\text{NaCl} + \text{Br}_2 \). Let's verify:

• Reactants: \( 2\text{NaBr} \) (2 Na, 2 Br) and \( \text{Cl}_2 \) (2 Cl).
• Products: \( 2\text{NaCl} \) (2 Na, 2 Cl) and \( \text{Br}_2 \) (2 Br). Atoms are balanced.

Answer:

The first box is \( \text{Na} \), the second box is \( \text{Cl} \), and the third box is \( \text{Br} \). So the completed equation is \( 2\text{NaBr} + \text{Cl}_2
ightarrow 2\boxed{\text{Na}}\boxed{\text{Cl}} + \boxed{\text{Br}}_2 \).