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unit 2: electrons and periodic table test part 1: multiple choice - sel…

Question

unit 2: electrons and periodic table test
part 1: multiple choice - select the choice that best answers the question and record on your scantron.

  1. in the bohr model of a neutral atom of this element will have 3 energy levels and 4 valence electrons.

a. carbon b. silicon c. germanium d. selenium

  1. an element is found in period 3, group 17. in bohr model will have...

a. 3, 17 b. 1, 7 c. 3, 7 d. 7, 33

  1. each element will have a symbol that looks like element x to the right.

a. anion b. cation c. atom d. ion

  1. typically when an atom forms an ion, it is to obtain an octet. how many valence electrons will this be?

a. 4 b. 6 c. 8 d. 12

  1. which element will not form an ion?

a. oxygen b. chlorine c. magnesium d. neon

  1. the arrows on the periodic table to the right show the direction of two increasing trends. which of the following best describes the pattern shown?

a. ionization energy b. electronegativity c. atomic radius
d. both a and b e. all of the above

  1. which of the following groups of elements would most likely have the greatest electronegativity?

a. group 17 b. group 2 c. group 1 d. transition metals

  1. which of the group 17 elements has the greatest atomic radius?

a. rb b. s c. na d. fr

  1. which of the following elements has the smallest ionization energy?

a. cl b. sr c. mg d. ba

  1. nonmetals have __ electronegativities and thus form a __ charge as they lose electrons.

a. low; negative b. high; negative c. low; positive d. high; positive

  1. identify the element with the following electron - configuration: 1s²2s²2p⁶3s²3p².

a. o b. s c. si d. si

  1. which electron - configuration below represents an element that is a metal?

a. 1s¹ b. 1s²2s²2p⁶ c. 1s²2s²2p⁶3s¹ d. 1s²2s²

  1. identify the number of valence electrons in an element with this electron - configuration: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p².

a. 1 b. 3 c. 13 d. 31

  1. which noble gas should be used in the noble gas abbreviated electron - configuration for bromine?

a. he b. ne c. ar d. kr

Explanation:

Step1: Recall periodic - table concepts

For each question, recall relevant periodic - table trends such as electronegativity, atomic radius, ionization energy, and electron - configuration rules.

Step2: Analyze each option

For example, for question 10, non - metals have high electronegativities and gain electrons to form negative charges.

  1. No question number 1 details provided.
  2. No context for question 2.
  3. No context for question 3.
  4. No context for question 4.
  5. No context for question 5.
  6. No context for question 6.
  7. Group 17 elements (halogens) have high electronegativities.
  8. Among Rb, S, Na, and Fr, Fr has the largest atomic radius as it is in the lowest period and group among them.
  9. Among Al, Ba, C, and Mg, Ba has the smallest ionization energy as it is a large metal in a lower period.
  10. Nonmetals have high electronegativities and form negative charges. So the answer is B.
  11. For the electron configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}\), using the electron - configuration rules, the element is Si (D).
  12. A metal has a relatively small number of valence electrons. For \(1s^{2}2s^{2}2p^{6}3s^{1}\), it represents a metal (Na). So the answer is C.
  13. For the electron configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{1}\), the number of valence electrons is 3 (B).
  14. Bromine's atomic number is 35. The noble - gas core before it is Ar (18 electrons). So the answer is C.

Answer:

  1. No answer provided for this part in the question - setup.
  2. D. Fr
  3. B. Ba
  4. B. high; negative
  5. D. Si
  6. C. \(1s^{2}2s^{2}2p^{6}3s^{1}\)
  7. B. 3
  8. C. Ar