Question

use the codes below to determine the type of reaction
s=synthesis d=decomposition sr=single replacement dr=double replacement c=combustion

1. p + o₂ → p₄o₁₀
2. c₅h₉o + o₂ → co₂ + h₂o
3. hgo → hg + o₂
4. al₂o₃ → al + o₂
5. cl₂ + nabr → nacl + br₂
6. h₂ + n₂ → nh₃
7. na + br₂ → nabr
8. cucl₂ + h₂s → cus + hcl
9. hgo + cl₂ → hgcl + o₂
10. c + h₂ → ch₄
11. k(clo₃) → kcl + o₂
12. s₈ + f₂ → sf₆
13. mg + o₂ → mgo
14. c₈h₁₆ + o₂ → co₂ + h₂o
15. bacl₂ + na₂(so₄) → nacl + ba(so₄)
16. nh₃ + h₂(so₄) → (nh₄)₂(so₄)
17. pb + h₃(po₄) → h₂ + pb₃(po₄)₂
18. hbr + al(oh)₃ → h₂o + albr₃
19. mgcl₂ + li₂(co₃) → mg(co₃) + licl

Explanation:

Let's solve each reaction type one by one:

1. \( \text{P} + \text{O}_2

ightarrow \text{P}_4\text{O}_{10} \) (corrected formula, assuming \( \text{P}_4\text{O}_{10} \))

Step1: Identify reaction type

Synthesis (S) reactions combine substances into one. Here, P and \( \text{O}_2 \) combine to \( \text{P}_4\text{O}_{10} \).

Answer:

S

2. \( \text{C}_5\text{H}_9\text{O} + \text{O}_2

ightarrow \text{CO}_2 + \text{H}_2\text{O} \)

Step1: Identify reaction type

Combustion (C) reactions involve a compound reacting with \( \text{O}_2 \) to form \( \text{CO}_2 \) and \( \text{H}_2\text{O} \). This fits combustion.