Question

use the following information to answer the next question. four reaction equations: in(s) + la³⁺(aq) → no reaction, np(s) + la³⁺(aq) → np³⁺(aq) + la(s), np(s) + nd³⁺(aq) → np³⁺(aq) + nd(s), la(s) + nd³⁺(aq) → no reaction. 4. arrange in order from strongest to weakest, the oxidizing agents above are numbered __, , , and __. record all four digits of your answer in the numerical - response section on the answer sheet. record your answer with no space and comma.

Explanation:

Step1: Understand oxidizing agent concept

An oxidizing agent is reduced in a reaction. A stronger oxidizing agent has a greater tendency to be reduced.

Step2: Analyze the reactions

From the given reactions, we can see that in the reactions involving $\text{La}^{3 + }$, $\text{Nd}^{3+}$, $\text{Np}^{3+}$ and $\text{In}^{3+}$, the more reactive metal (in terms of oxidation - reduction) will correspond to the weaker oxidizing agent among its ion form.

Step3: Determine the order

Based on the non - reaction and reaction data, we can infer that the order of oxidizing agents from strongest to weakest is $\text{In}^{3+},\text{Np}^{3+},\text{Nd}^{3+},\text{La}^{3+}$

Answer:

5,6,7,8