Question

use the periodic table to complete each nuclear fusion equation.\\(\ce{_{1}^{2}h + _{1}^{3}h \to _{b}^{a}he}\\)\\(\ce{_{7}^{14}n + _{1}^{1}h \to _{d}^{c}e}\\)\\(a:\square\\)\\(b:\square\\)\\(c:\square\\)\\(d:\square\\)\\(e:\square\\)

Explanation:

Step1: Balance mass numbers (1st eq)

Sum reactant mass numbers: $2 + 3 = A$

Step2: Balance atomic numbers (1st eq)

Sum reactant atomic numbers: $1 + 1 = B$

Step3: Balance mass numbers (2nd eq)

Sum reactant mass numbers: $14 + 1 = C$

Step4: Balance atomic numbers (2nd eq)

Sum reactant atomic numbers: $7 + 1 = D$

Step5: Identify element (2nd eq)

Element with atomic number $D=8$ is oxygen (O)

Answer:

A: $5$
B: $2$
C: $15$
D: $8$
E: $\text{O}$