Question

use the phase diagram of substance x below to find the melting point of x when the pressure above the solid is 0.60 atm. note: your answer must be within 20 °c of the exact answer to be graded correct.

Explanation:

Step1: Locate pressure on y - axis

Locate 0.60 atm on the pressure (y - axis) of the phase - diagram.

Step2: Find intersection with solid - liquid line

Draw a horizontal line at 0.60 atm until it intersects the solid - liquid co - existence curve.

Step3: Read temperature value

Read the temperature (x - axis) at the intersection point. Let's assume from the graph reading we get the temperature in Kelvin as $T_{K}$.

Step4: Convert Kelvin to Celsius

Use the conversion formula $T_{C}=T_{K}- 273.15$.

Answer:

(Assuming the graph reading gives $T_{K} = 300$ K) $T_{C}=300 - 273.15=26.85^{\circ}C$ (The actual value will depend on the accurate reading from the given phase - diagram)