Question

using the supplied solubility curve, determine the type of solution formed if 10 grams of ce2(so4)3 were dissolved in 100 grams of water at 50°c. unsaturated saturated supersaturated

Explanation:

Step1: Locate solubility on curve

Find the solubility of Ce₂(SO₄)₃ at 50°C on the given solubility - curve.

Step2: Compare with given amount

The amount of Ce₂(SO₄)₃ given is 10 grams in 100 grams of water. Compare this with the solubility value from the curve. If the given amount is less than the solubility at 50°C, it's unsaturated; if equal, it's saturated; if more, it's supersaturated.
(However, since the solubility - curve is not provided here, we assume a general approach. If the solubility of Ce₂(SO₄)₃ at 50°C is greater than 10 g/100 g water, the solution is unsaturated. If it is equal to 10 g/100 g water, the solution is saturated. If it is less than 10 g/100 g water, the solution is supersaturated.)

Answer:

We need the solubility - curve to accurately determine if the solution is unsaturated, saturated, or supersaturated. But if we assume the solubility of Ce₂(SO₄)₃ at 50°C is known: If solubility > 10 g/100 g water, unsaturated; if solubility = 10 g/100 g water, saturated; if solubility < 10 g/100 g water, supersaturated.