Question

1. the volume of 2.50 mol of nh₃(g) at stp is ____________. (record your answer in the numerical - response section below.)

Explanation:

Step1: Recall molar - volume at STP

At STP (Standard Temperature and Pressure, $T = 273\ K$ and $P= 1\ atm$), the molar volume of any ideal gas is $V_m=22.4\ L/mol$.

Step2: Use the formula for volume of a gas

The formula for the volume $V$ of a gas in terms of number of moles $n$ and molar volume $V_m$ is $V = n\times V_m$. Given $n = 2.50\ mol$ and $V_m=22.4\ L/mol$. Then $V=2.50\ mol\times22.4\ L/mol$.

Step3: Calculate the volume

$V = 2.50\times22.4=56.0\ L$

Answer:

56.0