Question

what would be the balanced formula for a compound made from beryllium and chlorine based on balance of charges?
a) becl₃
b) 2becl
c) be₂cl
d) becl

Explanation:

Step1: Determine charges of ions

Beryllium (Be) is in group 2, so it forms \(Be^{2+}\) ions. Chlorine (Cl) is in group 17, so it forms \(Cl^-\) ions.

Step2: Balance charges

To balance the positive and negative charges, we need 2 \(Cl^-\) ions to balance 1 \(Be^{2+}\) ion? Wait, no—wait, actually, let's do the criss - cross method. The charge of Be is +2, charge of Cl is -1. So the formula is \(BeCl_2\)? Wait, no, the options are \(BeCl_2\) (option A?), wait the options: A. \(BeCl_2\), B. \(2BeCl\), C. \(Be_2Cl\), D. \(BeCl\). Wait, no, maybe I made a mistake. Wait, Beryllium is +2, Chlorine is -1. So the formula should be \(BeCl_2\) (since \(2\times(-1)+(+2)=0\)). Wait, but the options: A is \(BeCl_2\), B is \(2BeCl\) (which is a coefficient, not a formula), C is \(Be_2Cl\) (wrong), D is \(BeCl\) (wrong). Wait, maybe the question has a typo, but among the options, the correct formula based on charge balance (Be²⁺ and Cl⁻, so 1 Be²⁺ and 2 Cl⁻, formula \(BeCl_2\)) is option A? Wait no, the original options: A. \(BeCl_2\), B. \(2BeCl\), C. \(Be_2Cl\), D. \(BeCl\). Wait, maybe I messed up the charge of Beryllium? No, Beryllium is group 2, so +2. Chlorine is group 17, -1. So the correct formula is \(BeCl_2\), which is option A. Wait, but the poll in the image has B selected, but maybe that's a mistake. Wait, let's re - evaluate. Wait, maybe the question is about Beryllium and Chlorine, and the correct formula is \(BeCl_2\) (option A). Wait, no, maybe the options are miswritten. Wait, the problem says "balanced formula for a compound made from Beryllium and Chlorine based on balance of charges". Beryllium (Be) has a charge of +2, Chlorine (Cl) has a charge of -1. To balance the charges, we need two Cl⁻ ions for one Be²⁺ ion. So the formula is \(BeCl_2\), which is option A. But the poll in the image shows B selected, but that might be an error. Wait, maybe the question is about Beryllium (Be⁺) and Chlorine? No, Beryllium is +2. Wait, perhaps the options are different. Wait, the options given: A. \(BeCl_2\), B. \(2BeCl\), C. \(Be_2Cl\), D. \(BeCl\). So the correct answer should be A. \(BeCl_2\) because the charge of Be is +2 and Cl is -1, so the formula is \(BeCl_2\) (since \(2\times(-1)+(+2)=0\)).

Answer:

A. \(BeCl_2\)