Question

what is the half - life for a particular reaction if the rate law is rate = (1171 min^(-1))a?

Explanation:

Step1: Identify the reaction order

The rate law is rate = k[A], which is the form of a first - order reaction where k = 1171 min⁻¹.

Step2: Use the half - life formula for first - order reactions

The half - life formula for a first - order reaction is $t_{1/2}=\frac{\ln 2}{k}$.

Step3: Substitute the value of k

Substitute k = 1171 min⁻¹ into the formula: $t_{1/2}=\frac{\ln 2}{1171\ min^{-1}}$.
Since $\ln 2\approx0.693$, then $t_{1/2}=\frac{0.693}{1171\ min^{-1}}\approx6.09\times 10^{-4}\ min$.

Answer:

$6.09\times 10^{-4}\ min$