Question

1. what happened when the charged balloon was brought near water?
2. what happened when the charged balloon was brought near hexane?
3. using the properties in the lewis structure table, explain why the liquids behaved differently

Explanation:

Step1: Analyze water - charge interaction

Water is a polar molecule. When a charged balloon is brought near water, the polar water molecules are attracted to the charged balloon due to electrostatic forces. The stream of water will bend towards the charged balloon.

Step2: Analyze hexane - charge interaction

Hexane is a non - polar molecule. Non - polar molecules do not have a significant charge separation. So, when a charged balloon is brought near hexane, there is no noticeable electrostatic attraction, and the hexane will not be affected by the charged balloon.

Step3: Explain based on Lewis structure properties

Water has a bent Lewis structure with a net dipole moment due to the electronegativity difference between oxygen and hydrogen, making it polar and responsive to charge. Hexane has a symmetrical Lewis structure of carbon - hydrogen chains with no net dipole moment, making it non - polar and unresponsive to the charged balloon.

Answer:

1. The stream of water bends towards the charged balloon.
2. There is no noticeable effect on hexane.
3. Water is polar (due to its Lewis - structure based dipole moment) and is attracted to the charged balloon, while hexane is non - polar (symmetrical Lewis structure with no net dipole) and is not affected by the charged balloon.