Question

what mass of aluminum sulfate is required to generate 10.0 grams of aluminum phosphate? molar mass alpo₄ = 121.95 g/mol molar mass al₂(so₄)₃ = 342.13 g/mol 2na₃po₄ + al₂(so₄)₃ → 2alpo₄(s) + 3na₂so₄ ? g al₂(so₄)₃

Explanation:

Step1: Calculate moles of \( \text{AlPO}_4 \)

Moles = \( \frac{\text{Mass}}{\text{Molar Mass}} \), so moles of \( \text{AlPO}_4 = \frac{10.0\ \text{g}}{121.95\ \text{g/mol}} \approx 0.0820\ \text{mol} \).

Step2: Relate moles of \( \text{AlPO}_4 \) to \( \text{Al}_2(\text{SO}_4)_3 \)

From the reaction, 2 moles of \( \text{AlPO}_4 \) come from 1 mole of \( \text{Al}_2(\text{SO}_4)_3 \). So moles of \( \text{Al}_2(\text{SO}_4)_3 = \frac{0.0820\ \text{mol}}{2} = 0.0410\ \text{mol} \).

Step3: Calculate mass of \( \text{Al}_2(\text{SO}_4)_3 \)

Mass = Moles × Molar Mass, so mass = \( 0.0410\ \text{mol} × 342.13\ \text{g/mol} \approx 14.0\ \text{g} \).

Answer:

\( 14.0\ \text{g} \) (or approximately \( 14\ \text{g} \))