Question

what is the mole ratio of $\text{ca(oh)}_2$ to $\text{caso}_4$ in the following reaction:
$\text{al}_2(\text{so}_4)_3 + 3\text{ca(oh)}_2
ightarrow 3\text{caso}_4 + 2\text{al(oh)}_3$
(use whole numbers.)
$square:square$

Explanation:

Step1: Identify stoichiometric coefficients

The balanced reaction is:

$$\text{Al}_2(\text{SO}_4)_3 + 3\text{Ca(OH)}_2 ightarrow 3\text{CaSO}_4 + 2\text{Al(OH)}_3$$

Coefficient of $\text{Ca(OH)}_2$ is 3; coefficient of $\text{CaSO}_4$ is 3.

Step2: Simplify the mole ratio

Divide both coefficients by their greatest common divisor (3):
$\frac{3}{3}:\frac{3}{3} = 1:1$

Answer:

$1:1$