Question

what nacl concentration results when 294 ml of a 0.780 m nacl solution is mixed with 447 ml of a 0.340 m nacl solution? concentration: m

Explanation:

Step1: Calculate moles in first solution

Use formula $n = M\times V$. For first solution, $V_1=294\ mL = 0.294\ L$ and $M_1 = 0.780\ M$. So $n_1=0.780\ mol/L\times0.294\ L = 0.22932\ mol$.

Step2: Calculate moles in second solution

For second solution, $V_2 = 447\ mL=0.447\ L$ and $M_2 = 0.340\ M$. So $n_2=0.340\ mol/L\times0.447\ L=0.15198\ mol$.

Step3: Calculate total moles

$n_{total}=n_1 + n_2=0.22932\ mol+ 0.15198\ mol = 0.3813\ mol$.

Step4: Calculate total volume

$V_{total}=V_1 + V_2=0.294\ L+0.447\ L = 0.741\ L$.

Step5: Calculate final concentration

Use formula $M=\frac{n}{V}$. So $M_{final}=\frac{0.3813\ mol}{0.741\ L}=0.514575\ M\approx0.515\ M$.

Answer:

$0.515$