Question

what is the oxidation state of sulfur in so₃²⁻?
a. 0
b. -2
c. +3
d. +4
e. +6
clear my choice

Explanation:

Step1: Recall oxidation state rules

Oxygen usually has an oxidation state of -2 (except in peroxides, etc.). Let the oxidation state of S be \( x \). The overall charge of \( \text{SO}_3^{2-} \) is -2.

Step2: Set up the equation

For \( \text{SO}_3^{2-} \), we have \( x + 3\times(-2)= -2 \).

Step3: Solve for \( x \)

Simplify the equation: \( x - 6 = -2 \). Add 6 to both sides: \( x = -2 + 6 = +4 \).

Answer:

d. +4