Question

what is the total number of oxygen atoms on the right - hand side of this chemical equation? 2cr(co)6(s)+4koh(aq)→khc r 2(co)10(aq)+k2co3(aq)+khcoo(aq)+h2o(l)

Explanation:

Step1: Analyze oxygen in $KHCr_2(CO)_{10}$

There are 10 oxygen atoms from the 10 $CO$ groups.

Step2: Analyze oxygen in $K_2CO_3$

There are 3 oxygen atoms in $K_2CO_3$.

Step3: Analyze oxygen in $KHCOO$

There are 2 oxygen atoms in $KHCOO$.

Step4: Analyze oxygen in $H_2O$

There is 1 oxygen atom in $H_2O$.

Step5: Calculate total oxygen atoms

$10 + 3+2 + 1=16$

Answer:

16